Print days of week using enum

This C program uses enumerated types to display days of week. The enumerated type is then declared as a different name using typedef keyword i.e. enum days to typedef enum days days

The function prints for each day of the week, today, yesterday, and tomorrow, both as a string and as a number.

#include <stdio.h>

/* Introducing an enumerated data type */
enum days { monday, tuesday, wednesday, thursday, friday, saturday, sunday};
typedef enum days days; // This allows us to use "days" as an abbreviation
                        // for "enum days"

/* Two useful functions */
days yesterday(days today){
  return (today + 6) % 7;
}
days tomorrow(days today){
  return (today + 1) % 7;
}

// A useful array: thedays is an array of constant (i.e. you cannot
// modify them) pointers to constant (i.e. you cannot modify them) strings
const char * const thedays[] = {
          "monday", "tuesday", "wednesday", "thursday",
         "friday", "saturday", "sunday"
};

int main(void){
  days today;

  printf("today    \tyesterday  \ttomorrow\n ============================================\n");
  for (today=monday;today<=sunday;today++)
    printf("%s = %d \t %s = %d \t %s = %d\n",
    thedays[today], today,
    thedays[yesterday(today)], yesterday(today),
    thedays[tomorrow(today)], tomorrow(today));
}

#include <stdio.h>

/* Introducing an enumerated data type */

enum days { monday, tuesday, wednesday, thursday, friday, saturday, sunday};

typedef enum days days; // This allows us to use "days" as an abbreviation

// for "enum days"

/* Two useful functions */

days yesterday(days today){

return (today + 6) % 7;

}

days tomorrow(days today){

return (today + 1) % 7;

}

// A useful array: thedays is an array of constant (i.e. you cannot

// modify them) pointers to constant (i.e. you cannot modify them) strings

const char * const thedays[] = {

"monday", "tuesday", "wednesday", "thursday",

"friday", "saturday", "sunday"

};

int main(void){

days today;

printf("today \tyesterday \ttomorrow\n ============================================\n");

for (today=monday;today<=sunday;today++)

printf("%s = %d \t %s = %d \t %s = %d\n",

thedays[today], today,

thedays[yesterday(today)], yesterday(today),

thedays[tomorrow(today)], tomorrow(today));

}

The output of the above program is

today     yesterday   tomorrow
============================================
monday = 0   sunday = 6   tuesday = 1
tuesday = 1   monday = 0   wednesday = 2
wednesday = 2   tuesday = 1   thursday = 3
thursday = 3   wednesday = 2   friday = 4
friday = 4   thursday = 3   saturday = 5
saturday = 5   friday = 4   sunday = 6
sunday = 6   saturday = 5   monday = 0

today yesterday tomorrow

============================================

monday = 0 sunday = 6 tuesday = 1

tuesday = 1 monday = 0 wednesday = 2

wednesday = 2 tuesday = 1 thursday = 3

thursday = 3 wednesday = 2 friday = 4

friday = 4 thursday = 3 saturday = 5

saturday = 5 friday = 4 sunday = 6

sunday = 6 saturday = 5 monday = 0