Home Forums C Programming some math problems in C

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    • #1997
      EvangelineBush33
      Participant

      I want to calculate secant method using C language
      That is a program—->

      #include
      #include
      #include
      main()
      {
      double fx(double x);
      double x0,x1,x2,f0,f1,f2,err;
      int n,i;
      printf("nn f(x) =x*x*x-5*x-7");
      printf("nnEnter an interval [x0,x1] in"
      " which root is to be found");
      printf("nx0 =");
      scanf("%f",&x0); /* INTERVAL[x0,x1] is to be entered here */
      printf("x1=");
      scanf("%f",&x1);
      printf("n Enter the number of iterations=");
      scanf("%d",&n);
      printf("npress any key for display of iterations...n");
      getchar();
      i=0;
      while (n > 0)
      {
      f0=fx(x0);
      f1=fx(x1);
      x2 = x1-((x1-x0)/(f1-f0))*f1;
      i++;
      printf("n x[%d]=%f x[%d]=%f",i,i-1,x0,i,x1);
      printf("n f[%d]=%f f[%d]=%f",i,i-1,f0,i,f1);
      printf("n x[%d]=%f",i+1,x2);
      x0=x1;
      x1=x2;
      getchar();
      }
      printf("nnThe value of root is =%f",x2);
      }
      double fx(double x)
      {
      double f;
      f=x*x*x-5*x-7;
      return(f);
      }

      But while running not the erreo is displayed but the results displayed is
      f(x) =x*x*x-5*x-7

      Enter an interval [x0,x1] in which root is to be found
      x0 =2.5
      x1=3

      Enter the number of iterations=4

      press any key for display of iterations…

      x[1]=0.000000 x[0]=0.000000
      f[1]=-7.000000 f[0]=-7.000000
      x[2]=inf

      Means not able to calculate root as seen in the output it is x[1]=0…

      so what will be the problem????

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