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How to count all the three digit number tht lie between 100 to 300 and whose 1st & last digit is 2?
Ans:

C

#include <iostream> using namespace std; void display() {  int count = 0;  for(int i = 100;i<300;i++)  {   int value = i;   if(((value%10)== 2) &&(value/100)==2)   {    cout<<value<<endl;    count++;   }  }  cout<<"Total Number "<<count<<endl; } void main() {  display(); } output: 202 212 222 232 242 252 262 272 282 292 Total Number 10

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#include <iostream> using namespace std; void display() {  int count = 0;  for(int i = 100;i<300;i++)  {   int value = i;   if(((value%10)== 2) &&(value/100)==2)   {    cout<<value<<endl;    count++;   }  }  cout<<"Total Number "<<count<<endl; } void main() {  display(); }   output: 202 212 222 232 242 252 262 272 282 292 Total Number 10

• This reply was modified 8 years, 10 months ago by M. Saqib.
• This reply was modified 4 years, 2 months ago by M. Saqib.
• This reply was modified 4 years, 2 months ago by M. Saqib.
• This reply was modified 4 years, 2 months ago by M. Saqib.

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